Ammonia gas (NH3) gas, hydrogen and nitrogen The reaction is done by the gas. Write a balanced equation. How many grams of nitrogen gas to ammonia requires 34g is production. I know I worked so hard. Are more. Please explain step by step.
Equations: Nitrogen (gas) + Hydrogen (gas) - "ammonia nitrogen gas for Formula: N2 chemical formula for hydrogen gas: H2 and ammonia gas Formula: NH3 and then the above equation can be written as : N2 + H2, etc. - "NH3 equation," "When the elements of the RHS is the same as the amount of each type of LHS is called a balance. Now, we balance the equation 1. There may LHS 2 Ns (Example: N2), so the amount of N 2 In the RHS of Should be. How do we get it? 2 NH3 multiplied. So we get: N2 + H2, etc. - "2 (NH3) 2. N as, but Joe H is not balanced yet. There RHS 6 HS, so that we LHS 6 HS Must have. In other words, the growth we have achieved 3 H2. Now We get: N2 + 3 (H2, etc.) - "2 (NH3), we calculate that the problem now 1 What's going on is a balanced equation .. In the periodic table of elements, N We know the atomic mass of 14 H atoms of mass will have one. Therefore, the atomic mass of NH3 = 1 * 14 + 3 * 1 = 17 (there is 1 N and NH3 3 HS) is. 2 NH3 1 is for the mole. But the problem is that NH3 mass of 34, 2 * 17 is Is stated. That means there is a mole NH3 2. 2. Balance in the equation, we have a mole of nitrogen gas equation Use: N2 coefficient of = N2 / NH3 mole of the cell count can be * NH3 = 1 / 2 * 2 N2 = 1 3 of a mole of a mole. Now we calculate the mass of the N2. N2 = 21 mole of the N = 1 * 14 = 28g * atomic mass of the mass. (The answer)
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